TheSwamp
CAD Forums => Vertically Challenged => Architecturally Speaking => Topic started by: caddman6425 on August 10, 2011, 10:42:40 AM

Anybody good at trig here, I mean really good?

what is the question?
If you don't post it we can't help you....

Ah. I think he already ask question. Maybe you missed it so I will point out to you.
Anybody good at trig here, I mean really good?
There! Can you see he asked his question?
:P :P :evil: :evil: :)

Ah. I think he already ask question. Maybe you missed it so I will point out to you.
Anybody good at trig here, I mean really good?
There! Can you see he asked his question?
:P :P :evil: :evil: :)
uh, NO
he asked
A question.
As that isn't a question of Trigonometry, it is a question of ability to solve a trigonometric equation.
And THAT is the question he did NOT ask in a fully formed manner such that anyone; even if they are only mediocre at Trigonometry might be able to provide an answer. That is should he actually post the actual mathematical equation, or challenge he needs a solution, or the proper direction to achieve a solution to.
As it could be that any of us could rise to the challenge and provide said direction, or answer when and or if it is actually posted for our consideration.

Actually he asked if anyone was good at 'being in good condition', 'trim'
Definition of trig
http://www.thefreedictionary.com/trig (http://www.thefreedictionary.com/trig)

(http://www.theswamp.org/lilly_pond/alanjt/worf.gif)

Ah. I think he already ask question. Maybe you missed it so I will point out to you.
Anybody good at trig here, I mean really good?
There! Can you see he asked his question?
:P :P :evil: :evil: :)
uh, NO
he asked
A question.
As that isn't a question of Trigonometry, it is a question of ability to solve a trigonometric equation.
And THAT is the question he did NOT ask in a fully formed manner such that anyone; even if they are only mediocre at Trigonometry might be able to provide an answer. That is should he actually post the actual mathematical equation, or challenge he needs a solution, or the proper direction to achieve a solution to.
As it could be that any of us could rise to the challenge and provide said direction, or answer when and or if it is actually posted for our consideration.
Hook, line and Sinker!
**We really need that sarcasm smiley here at TheSwamp.**

Actually he asked if anyone was good at 'being in good condition', 'trim'
Definition of trig
http://www.thefreedictionary.com/trig (http://www.thefreedictionary.com/trig)
Perhaps the question posed in the OP was mistakenly incomplete, and he really meant to ask if anyone was good at 'trig[ging]', 'Stopping (a wheel) from rolling, as with a wedge.' :?
I mean, if I had to stop a wheel from rolling, I wouldn't want someone who's only mediocre at 'stopping (a wheel) from rolling'... I too would prefer someone who's 'Really good.' Just saying.

I mean, if I had to stop a wheel from rolling, I wouldn't want someone who's only mediocre at 'stopping (a wheel) from rolling'... I too would prefer someone who's 'Really good.' Just saying.
Except we only know about the ownership of a wheel. We don't have a clue what he's doing with it. (straight into Out of Context thread.)

(straight into Out of Context thread.)
LoL! linky (http://www.theswamp.org/index.php?topic=35052.msg443192#msg443192)
Edit: Figured I'd beat Jeff to the punch. LoL

Anybody good at trig here, I mean really good?
Given he posted this partial question over 2.5 hours ago, he must want someone that is really good and extremely SLOW at Trigonometry to help him out with this question.

Oh my GAWD.just answer the question already.
The answer is YES.
There problem solved....now we can get on with the rest of the excitement in our lives!

Oh my GAWD.just answer the question already.
The answer is YES.
There problem solved....now we can get on with the rest of the excitement in our lives!
:D :D
But Sorry; certifiable proof is needed along with your first born that you are "really good" at trigonometry.

Oh my GAWD.just answer the question already.
The answer is YES.
There problem solved....now we can get on with the rest of the excitement in our lives!
:D :D
But Sorry; certifiable proof is needed along with your first born that you are "really good" at trigonometry.
Wait, we actually accomplished something here?

Oh my GAWD.just answer the question already.
The answer is YES.
There problem solved....now we can get on with the rest of the excitement in our lives!
:D :D
But Sorry; certifiable proof is needed along with your first born that you are "really good" at trigonometry.
Wait, we actually accomplished something here?
Not yet by my simple standards. But getting closer.

Oh my GAWD.just answer the question already.
The answer is YES.
There problem solved....now we can get on with the rest of the excitement in our lives!
:D :D
But Sorry; certifiable proof is needed along with your first born that you are "really good" at trigonometry.
Wait, we actually accomplished something here?
Not yet by my simple standards. But getting closer.
2+2=5

Better idea, why doesn't the OP just get 'good'... 'really good' at trigonometry on their own:
Learn trigonometry at Khan Academy (http://www.khanacademy.org/#trigonometry)

Better idea, why doesn't the OP just get 'good'... 'really good' at trigonometry on their own:
Learn trigonometry at Khan Academy (http://www.khanacademy.org/#trigonometry)
Khaaaaaan!

:)
Anybody good at trig here, I mean really good?
yes.
edit: sorry, I should have read the complete thread before posting ... seems the question has been answered.

Anybody good at trig here, I mean really good?
yes.
HaHa. Sentence structuring and grammar.

You guys are seriously afflicted ...
Now that the question has been answered in the affirmative .. if you haven't seriously pissed off yet another newt swamper, then perhaps at some point we can get him to develop his thoughts more.
I guess everyone here already knows everything and they never had the occasion to have to ask anyone for anything. It must be a nice bubble you are living in.

I am guilty and apologize,
Hopefully he understands that it had nothing to do with him and will reply.
He has not been active since all these posts and would be great if they disappeared.

I am guilty and apologize,
Hopefully he understands that it had nothing to do with him and will reply.
He has not been active since all these posts and would be great if they disappeared.
Oh come on, post #5 (http://www.theswamp.org/index.php?topic=39110.msg443179#msg443179) is solid gold. :roll:

I guess everyone here already knows everything and they never had the occasion to have to ask anyone for anything.
Yes, I've had to ask, and I do so by asking a question that is derived to achieve the answer I needed, not find out if someone might have the ability or aptitude to answer. Because there is a difference.
Note:
Is anyone here good at trig, I mean really good
VS
Can someone tell me how to solve for or provide a solution to calculating the included angle in the following trigonometric equation? (Enter your equation here)
Which form do you believe will get me the answer or the process to answer the mathematical challenge I am being pressed with?

I am guilty and apologize,
Hopefully he understands that it had nothing to do with him and will reply.
He has not been active since all these posts and would be great if they disappeared.
Oh come on, post #5 (http://www.theswamp.org/index.php?topic=39110.msg443179#msg443179) is solid gold. :roll:
Khan trumps Star Trek... Especially given Keith's moaning. :wink:

Thanks all, I guess I really deserved this. The question that I need help with is really long and drawn out, so I was thinking that before I tried to type everything out, I'd better find out if there was some people available right at the present to help. I thought that I'd notified when I got answers, but I guess not, and I got so caught up trying to solve the problem that I forgot to check. Sorry all. I'm attaching a drawing and I guess well start from there. I'm trying to sole "o"

Are trying to find the arch length between 2 points is so using trim

This is why I say that it is going to take some time to explain what I'm trying to accomplish. There is four sections to the drawing. The first is the text, the second is the portion of the drawing that looks like a mess. The two parell arcs represent a arched steal beam. I'm trying to come up with an equation so as to solve the plum cut of the beam at any point along 1/2 the periphery of the arc. The triangle that is formed by the beam depth and the unknown vertical cut, forms an oblique triangle, the oppsite side is not tangent to the arc. The only knowns are the beam depth which is 10 and the adjcent angle of 19.47 deg. I can sovle the right triangle with the angle an Hyp as well as the opp side, but I can sole the other angle of the oblique triangle since I don't have enough knowns. This is where I need help, I've stared so close at all the trees, that I don't see the forest anymore. I know that it is solvable, but I can't figure where the relatinships are to get me where I want to go. There is a lot more, but I hate typing so I guess I'll go with the flow as it comes along.

I think that this is what you want:
o = SQRT((TAN(A)*10)^2 – (SIN(A)*10)^2)
Which should be 1.1785
The drawing has it at 1.1419, but the angle between the radius “c” and “h” is not 90 degrees. Should it be 90?

No it should not be 90, it isn't tangent to the arc. The vertical line that intersect the top arc is th plum cut length. When you form the triangle that small side is the intersection points of the triangle. If it was tangent, then I'd have no problem. You're equation is base on the ang being tangent or at 90 deg

I see it now.

How about:
o = (COS(ASIN((170*SIN(A)))/180))*180) – (COS(A)*180)

This may be more succinct:

Thanks all, I guess I really deserved this.
As mentioned before, we were picking on each other in good fun or at the very least I was. None of this was directed at you, we just use your O.P. to get us going which as you can see does not take much. And yes we get distracted with Squirrels and other things with bushy tails also. So do not take it heart.
From your problem I can see it is above my pay grade so I will leave it to the more knowledgeable ones.
Cheers.
Whoops forgot to read page three of this thread. Ahh excel to rescue.

Just the trig stuff..
[Edit] ... missed some text formatting ...

The above post proves my point; that a well formed question will yield a well formulated answer.
Although, I wonder why any use of 'trig' would be needed to 'solve' the unknown angles; given that it was drawn correctly in cad to start with?

Writting a routine that draws all Steal Beams as structural members. Can put into any configuration and in one configuration need to know the plum cut programaticaly for ofset bearing points. Yes I knew that it can be solved using lisp or a calculator but I had to prove it to understand it.

I want to thank everyone that contributed to this question. I did figre the solution this morning at about 2:00 A. M. but all of yours was helpfull.